Sum of digits#10801

Sum of digits (Editorial)

Since the input numbers can be very large (up to $50$ digits), read them as strings. Let $s$ be a string containing the number. For example, if $s = "123"$ s = "123", the digit at the $i$ -th position of the number will be $s [i] -^{'} 0^{'}$ s[i] - '0'. Sum the digits of the number at all positions.

Algorithm implementation

Read the number of test cases $n$ .

cin >> n;

Process $n$ test cases sequentially.

for (i = 0; i < n; i++)
{

Read the input number into the string $s$ .

  cin >> s;

Compute the sum of the digits of the number in the variable $s u m$ .

  sum = 0;
  for (j = 0; j < s.size(); j++)
    sum = sum + s[j] - '0';

Print the answer.

  cout << sum << endl;
}

Python implementation

Read the number of test cases $n$ .

tests = int(input())

Process $n$ test cases sequentially.

for _ in range(tests):

Read the number as a string. Convert the input string into a list of digits.

  lst = list(map(int,input()))

The sum of the numbers in the list $l s t$ is equal to the sum of the digits of the current number. Print the result.

  print(sum(lst))