Find the product 2 (Editorial)

We implement the desired expression , Python will be a great way to go.

The expression is

Which can be computed directly in $\mathcal{O}(n)$ and for $n\le 1000$ the estimation precision will be good enough in python.

n=int(input())
p=1
for i in range(1,n+1):
    p*=(1+(1/(i*i)))
print(p)