Problem Author: | De3b0o |
Prepared by: | De3b0o |
Edited by: | Hasan Saleh (MathModel) |
Solution
For a pair () to be majestic, it must satisfy the following condition:
a_i a_j
A pair () where (i,j \ge 1000) can't be majestic because then i \cdot j \ge 10^6 \ge a_i + a_j.
So we can for each , check if the pairs () (1 \le i \le \min(j,1000)) are majestic.
Complexity \mathcal{O}(1000 \cdot \sum(n)).
#include<bits/stdc++.h>
#define ll long long
#define d3 ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
using namespace std;
const ll N = 1e5+9;
ll n,ans;
ll a[N];
int main()
{
d3
ll T;
cin >> T;
while(T--)
{
cin >> n;
for(int i = 1 ; n>=i ; i++)
cin >> a[i];
ans=0;
for(int i = 1 ; n>=i ; i++)
{
for(int j = 1 ; min(i,1000)>=j ; j++)
{
if(a[i]+a[j]==i*j)
ans++;
}
}
cout << ans << "\n";
}
}