Iterate through the digits of the number . Find the number of digits in the number . If the number is negative, then change its sign to the opposite.
Read the input data. If the number is negative, then calculate its absolute value.
scanf("%d %d", &n, &a);
if (n < 0) n = -n;In the variable , count the number of digits .
res = 0;Iterate through the digits of the number .
while (n > 0)
{
if (n % 10 == a) res++;
n /= 10;
}Output the answer.
printf("%d\n", res);import java.util.*;
public class Main
{
public static void main(String[] args)
{
Scanner con = new Scanner(System.in);
int n = con.nextInt();
int a = con.nextInt();
if (n < 0) n = -n;
int res = 0;
while (n > 0)
{
if (n % 10 == a) res++;
n /= 10;
}
System.out.println(res);
con.close();
}
}n = int(input())
a = int(input())
if n < 0: n = -n
res = 0
while n > 0:
if n % 10 == a:
res += 1
n = n // 10
print(res)