Point#7451

Point

1 second

128 megabytes

Very easy

The point is given with its $x$ and $y$ coordinates: ( $x$ , $y$ ).

Two points ( $a$ , $b$ ), ( $c$ , $d$ ) and an integer $n$ are given. Add them.

Adding two points means to add the corresponding coordinates: ( $1$ , $2$ ) + ( $3$ , $4$ ) = ( $4$ , $6$ ).
Adding point and a number means to add a number to both point coordinates: ( $1$ , $2$ ) + $10$ = ( $11$ , $12$ ).

Write the code according to the next interface:

class Point // C++
{
private:
  int x, y;
public:
  Point(int x = 0, int y = 0); // Constructor
  void Read(void); // Read point coordinates
  void Print(void); // Print point coordinates
  Point operator +(int v); // Overload operator +: return the sum of point and integer v
  Point operator +(Point &p); // Overload operator +: return the sum of two points
  int getX(void); // Return x coordinate
  int getY(void); // Return y coordinate
  void SetX(int x); // Set x coordinate
  void SetY(int y); // Set y coordinate
};

C++

class Point // Java
{
  private int x, y;
  Point(int x, int y); // Constructor
  public String toString(); // Return the string with point coordinates
  public Point Add(int v); // Add to both point coordinates the value of v, return the point
  public Point Add(Point p); // Add point p, return the sum of two points
  public int getX(); // Return x coordinate
  public int getY(); // Return y coordinate
  public void SetX(int x); // Set x coordinate
  public void SetY(int y); // Set y coordinate
};

Java

Input

The first line contains the coordinates $a$ and $b$ of the first point. The second line contains the coordinates $c$ and $d$ of the second point. The third line contains an integer $n$ . All values do not exceed $10000$ by the absolute value.

Output

Print the sum of two points and a number.

Examples

Example 1