To solve this problem, use a conditional statement.
Algorithm implementation
Read the input temperature value .
scanf("%d", &t);Based on the value of , print the corresponding result.
if (t > 0)
printf("Water\n");
else
printf("Ice\n");Java implementation
import java.util.*;
public class Main
{
public static void main(String[] args)
{
Scanner con = new Scanner(System.in);
int t = con.nextInt();
if (t > 0)
System.out.println("Water");
else
System.out.println("Ice");
con.close();
}
}Python implementation
Read the input temperature value .
t = int(input())Based on the value of , print the corresponding result.
if t > 0:
print("Water")
else:
print("Ice")