Odds in the interval#8935

Odds in the interval (Editorial)

Use a for loop. Iterate through all numbers from $a$ to $b$ in ascending order and print only the odd ones.

Algorithm implementation

Read the input data.

scanf("%d %d", &a, &b);

Iterate through all numbers from $a$ to $b$ in ascending order and print only the odd ones.

for (i = a; i <= b; i++)
  if (i % 2 == 1) printf("%d ", i);

Java implementation

import java.util.*;

class Main 
{
  public static void main(String[] args) 
  {
    Scanner con = new Scanner(System.in);
    int a = con.nextInt();
    int b = con.nextInt();
    for(int i = a; i <= b; i++)
      if (i % 2 == 1) System.out.print(i + " ");
    con.close();
  }
}

Java

Python implementation

Read the input data.

a, b = map(int, input().split())

Iterate through all numbers from $a$ to $b$ in ascending order and print only the odd ones.

for i in range(a, b + 1):
  if i % 2 == 1: print(i, end=" ")

Python implementation — list

Read the input data.

a, b = map(int, input().split())

Create a list containing all the odd numbers from the interval $[a, b]$ .

res = [x for x in range(a, b + 1) if x % 2 != 0]

Print the answer.

print(*res)