Print array 4 (Editorial)

Read the input sequence into an array. Count the number of negative elements. If there are no negative numbers (the count is $0$), print "NO". Otherwise, first print the count of negative numbers, followed by the numbers themselves in reverse order.

Algorithm implementation

To store the sequence, declare an array $m$.

int m[101];

Read the input data.

scanf("%d", &n);
for (i = 0; i < n; i++)
  scanf("%d", &m[i]);

Count the number of negative elements in the variable $cnt$.

cnt = 0;
for (i = 0; i < n; i++)
  if (m[i] < 0) cnt++;

If there are no negative numbers in the array, print "NO".

if (cnt == 0)
  printf("NO\n");
else
{

Print the count of negative numbers.

  printf("%d\n", cnt);

Print the negative numbers in reverse order.

  for (i = n - 1; i >= 0; i--)
    if (m[i] < 0) printf("%d ", m[i]);
  printf("\n");
}

Python implementation

Read the input data.

n = int(input())
lst = list(map(int, input().split()))

Create a list negatives that contains only the negative numbers.

negatives = [x for x in lst if x < 0]

If there are no negative numbers in the array, print "NO".

if not negatives:
  print("NO")
else:

Otherwise, first print the count of negative numbers, followed by the negative numbers in reverse order.

  print(len(negatives))
  print(*negatives[::-1])